Example of C++ implementation of the multi source shortest path Floyd algorithm

In this paper, an example of C++ implementation of the multi-source shortest path Floyd algorithm is presented. I will share it with you for your reference as follows:

#include<cstdio>
#include<cstring>
#include<iostream>
#define MAX 999
using namespace std;
int n,m;
int e[MAX][MAX];
void Init()
{
  for(int i=1; i<=n; ++i)
    for(int j=1; j<=n; ++j)
    {
      if(i==j)
        e[i][j]=0;
      else
        e[i][j]=MAX;
    }
}
void Input()
{
  int a,b,c;
  for(int i=1; i<=m; ++i)
  {
    cin>>a>>b>>c;
    e[a][b]=c;
  }
}
void Floyd()
{
  for(int k=1; k<=n; k++)
    for(int i=1; i<=n; i++)
      for(int j=1; j<=n; j++)
        if(e[i][j]>e[i][k]+e[k][j])
          e[i][j]=e[i][k]+e[k][j];
}
void Output()
{
  for(int i=1; i<=n; ++i)
    for(int j=1; j<=n; ++j)
      cout<<"dis["<<i<<"]["<<j<<"] = "<<e[i][j]<<endl;
}
int main()
{
  while(1)
  {
    cout<<"n"<<endl;// The number of vertices 
    cin>>n;
    if(!n) break;
    cout<<"m"<<endl;// The number of edges 
    cin>>m;
    Init();
    Input();
    Floyd();
    Output();
  }
}

Floyd algorithm is an algorithm to find the shortest path of multiple points, and its core code is

void Floyd()
{
  for(int k=1; k<=n; k++)
    for(int i=1; i<=n; i++)
      for(int j=1; j<=n; j++)
        if(e[i][j]>e[i][k]+e[k][j])
          e[i][j]=e[i][k]+e[k][j];
}

I hope this article is helpful to you C++ programming.