An example of a search algorithm for diagrams implemented in C language

  • 2020-05-19 05:28:59
  • OfStack

The example of this article describes the C language implementation diagram search algorithm. I will share it with you for your reference as follows:

In the game, we often encounter the path planning problem, using the relevant algorithm of the graph, we learn by simple graph.

Graphs are usually represented in two ways, matrices and adjacency lists. Matrix representation is simple and fast, but when the matrix is sparse, there is the problem of space waste, and the efficiency will decline, while the adjacency list saves space, and the time efficiency is high because the edges are continuously accessed. In this article, we will represent the graph as an adjacency list.


#include<queue>
#include<stack>
using namespace std;
struct SE{
  int vIndex;
  int tag;
  SE* next;
};
struct SMap{
  SE* pE;
  int nnode;
};
void visit(SE *se){
  printf("%d\n", se->vIndex);
}
SMap* create_map(int matrix[][6], int n){
  SMap* pMap = new SMap();
  pMap->nnode = n;
  pMap->pE = new SE[n];
  memset(pMap->pE, 0, n*sizeof(SE));
  for (int i = 0; i<n; i++){
    pMap->pE[i].vIndex = i;
    pMap->pE[i].tag = 0;
    SE* p = &pMap->pE[i];
    for (int j = 0; j<n; j++){
      if (matrix[i][j] != 0){
        p->next = new SE();
        p->next->vIndex = j;
        p->next->tag = 0;
        p->next->next = NULL;
        p = p->next;
      }
    }
  }
  return pMap;
}
int BFS(SMap* pMap, int n){
  queue<SE*> q;
  for (int i = 0; i < n; i++){
    if (pMap->pE[i].tag == 0){
      q.push(&pMap->pE[i]);
      while (!q.empty()){
        SE *se = q.front();
        q.pop();
        if (pMap->pE[se->vIndex].tag == 1){
          continue;
        }
        visit(se);
        pMap->pE[se->vIndex].tag = 1;
        SE * p = se;
        while (p->next){
          p = p->next;
          if (pMap->pE[p->vIndex].tag == 0){
            q.push(p);
          }
        }
      }
    }
  }
  return 0;
}
int DFS(SMap* pMap, int n){
  stack<SE*> s;
  for (int i = 0; i < n; i++){
    if (pMap->pE[i].tag == 0){
      s.push(&pMap->pE[i]);
      while (!s.empty()){
        SE *se = s.top();
        s.pop();
        if (pMap->pE[se->vIndex].tag == 1){
          continue;
        }
        visit(se);
        pMap->pE[se->vIndex].tag = 1;
        SE * p = &pMap->pE[se->vIndex];
        stack<SE*> tmp;
        while (p->next){
          p = p->next;
          if (pMap->pE[p->vIndex].tag == 0){
            tmp.push(p);
          }
        }
        while (!tmp.empty()){
          s.push(tmp.top());
          tmp.pop();
        }
      }
    }
  }
  return 0;
}
int main(){
  int map[6][6] = {
    { 0, 1, 0, 1, 0, 0 },
    { 1, 0, 1, 1, 1, 0 },
    { 0, 1, 0, 1, 0, 0 },
    { 1, 1, 1, 0, 1, 0 },
    { 0, 1, 0, 1, 0, 1 },
    { 0, 0, 0, 0, 1, 0 }
  };
  SMap* smap = create_map(map, 6);
// BFS(smap, 6);
  DFS(smap, 6);
  return 0;
}

I hope this article has been helpful to you in the programming of C language.


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