The C language determines whether a string begins with str2
- 2020-05-19 05:17:42
- OfStack
The code is very concise, the function is also very simple, here is no more nonsense, the code is directly dedicated to everyone, there is a need for a small friend can come to reference
#include <stdlib.h>
#include <string.h>
#include <stdio.h>
/** judge str1 Whether or not to str2 At the beginning
* If it's a return 1
* Not return 0
* Returns the error -1
* */
int is_begin_with(const char * str1,char *str2)
{
if(str1 == NULL || str2 == NULL)
return -1;
int len1 = strlen(str1);
int len2 = strlen(str2);
if((len1 < len2) || (len1 == 0 || len2 == 0))
return -1;
char *p = str2;
int i = 0;
while(*p != '\0')
{
if(*p != str1[i])
return 0;
p++;
i++;
}
return 1;
}
/** judge str1 Whether or not to str2 At the end
* If it's a return 1
* Not return 0
* Returns the error -1
* */
int is_end_with(const char *str1, char *str2)
{
if(str1 == NULL || str2 == NULL)
return -1;
int len1 = strlen(str1);
int len2 = strlen(str2);
if((len1 < len2) || (len1 == 0 || len2 == 0))
return -1;
while(len2 >= 1)
{
if(str2[len2 - 1] != str1[len1 - 1])
return 0;
len2--;
len1--;
}
return 1;
}
You are welcome to play freely and expand