js gets the node of C selected by Treeview selects the CheckBox item

There are a lot of methods on the web, and they all have flaws in the first try. Finally, I found one that seemed to have less code and was satisfactory. The test result said that several functions did not exist, so I set breakpoint debugging and searched for useful fields for each property. Finally, I found it.
It is sorted as follows:
First, to get the checkbox node in treeview in javascript, you need to set some properties of the treeview node, which I added in the background code.

 
TreeNode newNode = new TreeNode(); 
newNode.Text =  " showText " ; 
newNode.Value =id; 
newNode.NavigateUrl = id; //  Can be used to in javascript Get what you need value or text value  
newNode.ShowCheckBox = true; // According to checkbox 
newNode.Expanded = false; // Nodes in the fold  
newNode.Checked = true; //checkbox The selected  

Get Treeview node with Input control: var tree = document. getElementById("treenameOrid").getElementsByTagName("input");
The top is checkbox, so tree selects the item with checkbox. It differs from var treeitem=document.getElementById("treenameorid"); Cannot traverse directly to get text and value;
if (tree[i].type == "checkbox" && tree[i].checked) {content}
Get the required values for each node: var s = tree[i]. nextSibling. pathname; I found out it cost me a lot of brain cells. To get a value with this property, you must set the property newNode.NavigateUrl = the required value;
Okay, now give me the complete code for an javascript:

 
var idlist; 
function GeSelectedNode() { 
var getAllNodes = ""; 
idlist = new Array(); // Instantiate array  
var tree = document.getElementById("treenameOrid").getElementsByTagName("input"); 
for (var i = 0; i < tree.length; i++) { 
if (tree[i].type == "checkbox" && tree[i].checked) { 
var s = tree[i].nextSibling.pathname; // To get a value with this property, you must set the property newNode.NavigateUrl =  Need the value of the ; 
getAllNodes += s + '/'; 
idlist.push(s); // Adds the value to the end of the array 1 Item;  
} 
} 
alert(tree.length); 
alert(getAllNodes); 
} 

Now, run it, see if it's the result you need, and if it's not, don't forget to set breakpoints and debug.